In a p $\mathrm{n}$ diode reverse biased at $5 \mathrm{~V}$, the generated capacitance is $20 \mathrm{pF}$. If the doping of the $\mathrm{p}$ side is doubled and the bias is change to $20 \mathrm{~V}$, what will be the change in capacitance? If now the bias is changed to $100 \mathrm{~V}$, then what will be the change?