When the reverse bias voltage is increased to $3 V_{r}$, the new depletion width $W'$ can be calculated as:
$W' = \sqrt{\dfrac{2 \epsilon (V_{bi} + 3V_{r})}{q N}}$
Comparing the two depletion widths, we get:
$\dfrac{W'}{W} = \sqrt{\dfrac{V_{bi} +
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