00:01
So in this problem, we're given data of time points and a number of events are.
00:09
So we're talking about the mean lifetime of milan's decaying.
00:16
So this is actually a numerical problem.
00:19
The problem actually wants you to make a graph using a computer.
00:23
So i've included this image where i've plotted data points against time where time is in microseconds.
00:31
So we're given this decay law.
00:35
So at time equals zero, the r values r not, it's going to work out to be a little over 200, something like that.
00:47
Because at 1 .5 microseconds is 55, and then it's just what ends up working out to roughly.
00:59
This tau constant is known to be 2 .197, and some more decimal places microseconds, to a fairly high precision.
01:11
So what this problem is doing, we have these data points.
01:15
We want to find tau approximately from the data points, and then figure out how far off that is from the real value.
01:28
So actually, i'll just put.
01:31
The r values here so it's 55 35 23 18 12 5.
01:46
Number of vents is decreasing as we want to decay.
01:52
So the log value of r is something you calculate from these r values.
02:00
So that's 4 .007, 3 .553 .5 .3 .1 .3 .1.
02:16
352 .890, 2 .485, 1 .60.
02:26
So the problem is telling you the graph log versus log of r versus time.
02:36
It tells you to scale it r over r not, but the solution key in the textbook does it as just log r.
02:49
So i did it the way the textbook has it.
02:52
So it wants you to fit, do a best fit line.
02:58
So, you know, if you're doing the computer problem, it's going to want you to put an actual line in the graph, but it's going to look something like that.
03:10
So the point of this is that the slope of this decay is defined by the value tau.
03:22
So so why is that? so we have this decay law up here.
03:33
So hold on.
03:37
So r divided by r0 equals e minus t, tau...