00:01
Hello and welcome to this video solution of numerate.
00:03
So here we are given that in a photoelectric experiments in which monochromatic light and a sodium photocathode are used.
00:14
We find a stopping potential of let's say v1 that is equal to 1 .85 volts for a wavelength lambda 1 we can write that is 3000 armstrong right and in the other one you have got v2 that is 0 .82 volts and lambda 2 that's around 4000 armstrong right.
00:41
From this data you have to determine the value of the planck constant the work function of the sodium in an electron volt right and the threshold wavelength.
00:52
So a to determine the planck's constant you have to apply the formula the kinetic energy k max will be equal to the energy supplied by the photon minus the work function phi right.
01:09
K max will be equal to ev1 this is the stopping potential that is given by hc by lambda 1 minus phi will remain constant in both the cases right.
01:23
Now this is ev2 that is equal to hc by lambda 2 minus phi right.
01:29
So you have got both this equation.
01:32
Now if you 1 and 2 from 1 and 2 if you just remove this phi okay eliminate this phi then h will come out to be as per the expression it's e times of you will be having e1 minus v2 over c times 1 by lambda 1 minus 1 by lambda 2 right.
02:00
So this is what you have.
02:02
Now what you can do is you can simply plug in all these values now like you have got 1.
02:13
You don't need to have this you can keep this e times of this is 1 .85 minus v2 is you have got 0 .82 right over c by c we can write like in terms of nanometers per second which is 3 times of 10 to the power of minus sorry 17 nanometers per second.
02:44
What i am doing is i just keeping electron volt and second right or sorry here we are given armstrong so armstrong per 7 you can so it's 10 to the power of 18 now per second here you will be having the values in armstrong which is 3000 minus 1 by 4000 right armstrong 1 by armstrong sort of like this right.
03:27
So if you just this will be the upper one will be in electron volts right...