00:01
Hi, in the given problem, the number of turns in the coil are n is equal to 200.
00:21
And area of the coil is a is equal to 12 centimeter square or we can say this is 12 into 10 dashed bar minus 4 meter square.
00:41
Initially, the plane of coil is perpendicular to the magnetic field means the angle between area vector and magnetic field is theta 1 is 0 degree and in a time duration of 0 .0 .0 second plane of the coil becomes parallel to the magnetic field means now the angle between area vector of the coil and the angle between area vector of the coil and.
01:11
Magnetic field becomes 90 degree.
01:17
Magnetic field in which this coil is rotating is given as b is equal to 6 .0 into 10 degrees of minus 5 tesla.
01:27
Now in the first part of the problem we have to find the magnetic flux through one turn.
01:36
So magnetic flux through each turn of the coil is given as 5 is equal to d .a.
01:57
Or we can say this is b a cost theta.
02:03
So initially before the coil starts rotating the flux will be given by 5 .1 is equal to 6 .0 into 10 dashpar minus 5 tesla into 12 into 10 dashed par minus 5 tesla into 12 into 10 dash par minus minus 4 meter square into cosine of 0 degree, which comes out to be 1, cause 0 degree is always 1.
02:32
So finally, this answer for the first answer for the first part of the problem, is flux linked through the one turn of the coil.
02:44
When it starts just to start rotating is 7 .2 into 10 dash minus 8 vapor.
02:53
First of the answer of this first part of the problem...