00:01
For this problem on the topic of electromagnetic waves, in a polarized light experiment, we have unpolarized light with intensity i0 incident upon polarizer 1.
00:11
1 and 3 are crossed at 90 degrees and the orientations are fixed during the experiment.
00:16
Polarizer 2 has an angle of 45 degrees, and at time t is equal to 0, it starts to rotate with angular velocity omega about the direction of propagation of light in a clockwise direction, as an observer is doing it toward the light source.
00:30
If the intensity of the light emerging from polarizer 3 is monitored, we want to find an expression for this intensity as a function of time, and we want to know how this expression would change from a, if polarizer 2 would then rotate about an axis that is parallel to the direction of propagation of light, but displaced by distance d, which is less than r, where r is the radius of the polarizer.
00:54
Now, the intensity of light passing through the first polarizer, i1, is equal to the incident intensity, i -0, over 2 and the angle between the transmission axis of the first and second polarizer as a function of time.
01:07
We'll call it theta 1 comma 2 and this is equal to 45 degrees plus omega t, where t is the time in seconds and omega is in radiance per second.
01:21
The intensity of the light passing the second polarizer i2 is equal to i1 cosine squared of the 1 -2 which is a half i0 cosine squared of 45 degrees plus omega t so this is i2 as a function of t the angle between the transmission axis of the second and third polarizer as a function of time theta 2 -3 is equal to 45 degrees minus omega t now the intensity of the light the third polarizer i3 is equal to i2 times the cosine squared of theta 2 3 which is a half i 0 cosine squared of 45 degrees plus omega t times cosine squared 45 degrees minus omega t which we can write as a half i0 into cosine of 45 degrees plus omega t cosine of 45 degrees minus omega t all squared this is i t as a function of time now we can use the trigonometric identity that cosine u cosine v is equal to a half of cosine u plus v plus cosine u minus v and this gives us the cosine of 45 degrees plus omega t times the cosine of 45 degrees minus omega t equal to a half into the cosine of 45 degrees plus omega t plus 45 degrees minus omega t plus the cosine of 45 degrees plus omega t...