Question
In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas release $20 \mathrm{~J}$ of heat and $8 \mathrm{~J}$ of work has done on the gas-If the initial internal energy of the gas was $30 \mathrm{j}$, then the final internal energy will be(A) $58 \mathrm{~J}$(B) $2 \mathrm{~J}$(C) $42 \mathrm{~J}$(D) $18 \mathrm{~J}$
Step 1
Mathematically, it can be represented as: \[ \Delta U = \Delta Q - \Delta W \] where \(\Delta U\) is the change in internal energy, \(\Delta Q\) is the heat added to the system, and \(\Delta W\) is the work done by the system. Show more…
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In a thermodynamic process, pressure of a fixed mass of gas is changed in such a manner that the gas releases $20 \mathrm{~J}$ of heat and $8 \mathrm{~J}$ of work is done on the gas. If internal energy of the gas was $30 \mathrm{~J}$, then the final internal energy will be (a) $42 \mathrm{~J}$ (b) $18 \mathrm{~J}$ (c) $12 \mathrm{~J}$ (d) $60 \mathrm{~J}$
Thermodynamics
Round 1
In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas releases $20 \mathrm{~J}$ of heat and $8 \mathrm{~J}$ of work is done on the gas. If initial internal energy of the gas was $30 \mathrm{~J}$, what will be the final internal energy? (a) $42 \mathrm{~J}$ (b) $12 \mathrm{~J}$ (c) $10 \mathrm{~J}$ (d) $18 \mathrm{~J}$
In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules gives out 20 J of heat and 10 J of work is done on the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be (a) 30 J (b) 20 J (c) 60 J (d) 40 J
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