00:01
So we'll start with a couple of equations.
00:02
We can say that the change in the volume of the mercury would be equalling to the volumetric thermal expansion coefficient for mercury multiplied by the volume, the initial volume, multiplied by delta t.
00:23
So the circumference of the capillary, 2 pi multiplied by r, we can say that the change in the circumference would be equalling the linear expansion, coefficient multiplied by the original circumference multiplied by delta t and the volume of a cylinder is equaling to pi r squared h and so we can say that the change in the volume of the spherical reservoir would be equalling then to three multiplied by alpha v sub s delta t and when the volume of the mercury expands, we can say that the excess mercury goes into the excess volume of the sphere.
01:12
And the height reached by this excess mercury would then be equal to the volume of the cylinder divided by pi r squared.
01:22
We know that r is equaling the circumference divided by 2 pi, which we know to be equal to the original circumference plus the change in the circumference divided by 2 pi, we can say that then r would be equal to c not multiplied by 1 plus alpha delta t.
01:45
This would then be divided by 2 pi again, and this would then be equal to 2 pi r not multiplied by 1 plus alpha delta t divided by 2 pi.
02:01
Of course the 2 pi is cancel out, and we find that r is going to be equaling to the original radius multiplied by 1 plus alpha delta t.
02:14
We can say from the equation for h, h would then be the volume of the volume change of the mercury minus the volume change of the spherical reservoir.
02:29
This would be divided by pi r squared.
02:34
And we can substitute h would then be equal to beta, mercury v -s -s -d delta -t minus 3 alpha v -s -s -d delta -t divided by pi, and then here instead of r, we'll substitute and say r not squared, multiplied by 1 plus alpha -delta -ttt quantity squared.
03:06
And simplifying a little bit, we have h equaling volume sub s delta t, volumetric thermal expansion coefficient for mercury minus three times the linear expansion coefficient.
03:25
This would be divided by, again, pi r not squared, multiplied by one plus alpha delta t quantity squared.
03:37
So for quarts, we have the, we're going to be using the, linear expansion coefficient for quartz.
03:43
We know the fractional change f would be equaling to 1 minus h for quartz divided by h for silica and after substituting both of these in we have that the fractional change is going to be equal to 1 minus and we then have beta for mercury minus 3 alpha quarts pi r not squared 1 plus alpha for silica the lunar efficiency coefficient for silica multiplied by delta t quantity squared this second term will then be divided by again beta for mercury minus 3 alpha for silica pi r not squared...