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In a titration experiment, $12.5 \mathrm{mL}$ of $0.500 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$neutralize $50.0 \mathrm{mL}$ of $\mathrm{NaOH}$. What is the concentration of the NaOH solution?

$$[N a O H]=0.25 \mathrm{M}$$

Chemistry 102

Chapter 16

Acid-Base Equilibria and Solubility Equilibria

Acid-Base Equilibria

Aqueous Equilibria

Carleton College

University of Kentucky

University of Toronto

Lectures

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

24:14

In chemistry, a buffer is a solution that resists changes in pH. Buffers are used to maintain a stable pH in a solution. Buffers are solutions of a weak acid and its conjugate base or a weak base and its conjugate acid, usually in the form of a salt of the conjugate base or acid. Buffers have the property that a small change in the amount of strong acid or strong base added to them results in a much larger change in pH. The resistance of a buffer solution to pH change is due to the fact that the process of adding acid or base to the solution is slow compared to the rate at which the pH changes. In addition to this buffering action, the inclusion of the conjugate base or acid also slows the process of pH change by the mechanism of the Henderson–Hasselbalch equation. Buffers are most commonly found in aqueous solutions.

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When you're doing problems like these, it's always best to start with a reaction so that you couldn't kind of visualize what's going on here. So we're told that we have some concentration of sulfuric acid reacting with some concentration off sodium hydroxide. We're forming some salt. In this case, it's sodium sulphate, and we're forming water. We're going to balance this equation first because you have to. Sodium is here one sodium? Here's we're going out to here. We have a total of four hydrogen on this side and we have to hydrogen on the side. So we're gonna add it to here in our fully balanced because we have four plus two. It's six oxygen's on our products side and six oxygen's on our react inside. So we're good to go here Now. Now we can start doing a simple story Key Metric conversion were given. That we have is your appoint 500 moller solution of sulfuric acid. We know that polarities that we write this down here. It's moles per liter. In order to do story que metric conversion, it's best to work with moles, so we're gonna convert this. Two moles were given that This is 12.5 mil leader solution of sulfuric acid. Remember, to convert from real leaders two leaders, This is quite to be 1000 the leaders in one leader. So this will cancel out our leaders, units and it'll leaders, units. Now we're left with moles of sulfuric acid in order to convert from wolves will use like geometry. So we're given that one mole H two s 04 We'll look back at our equation up here One mole of sulfuric acid toe every two moles of potassium hydroxide. So now we have our moles of Anyways, now we're final step is the gun, Bert from ALS two polarity So we can multiply this equation by are 50 mill leaders to get our volume on the denominator Remember to convert from the leaders Two leaders So we have 1000 liters One leader. So now we're canceling formal leaders were left with or moles of any wage. This is our units and our leaders at the bottom. If we finish this calculation will end up with 0.25 moles for leader off any a leech or other words 0.25 roller sodium hydroxide And that is your answer

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