In a transistor amplifier, β=62, RL=5000 Ωand internal resistance of the transistor is 500 Ω. Wh

step 1 So in this problem, I can write the value of voltage amplification, let it be AV, which is equal

In a transistor amplifier, β=62, RL=5000 Ωand internal...

In a transistor amplifier, $\beta=62, \mathrm{R}_{\mathrm{L}}=5000 \Omega$ and internal resistance of the transistor is $500 \Omega$. What will be the ratio of power amplification to voltage amplification?
(A) 61
(B) 62
(C) 60
(D) 100

Key Concepts

Transistor Current Gain (?)

This is the basic property of a bipolar transistor that relates the collector current to the base current (Ic = ? Ib). It is a measure of the transistor’s ability to amplify current and is fundamental in determining overall amplifier performance.

Voltage Gain in Amplifiers

Voltage amplification refers to the ratio of the output voltage to the input voltage of the amplifier. In transistor amplifiers, factors such as the load resistance and internal resistances of the transistor determine the magnitude of the voltage gain.

Power Gain in Amplifiers

Power gain is the ratio of the output power to the input power. Since power is proportional to the square of the voltage (for a given resistance), the power gain is closely related to the voltage gain but also takes into account the effect of the source and load impedances.

Relationship between Voltage and Power Gain

In a transistor amplifier, there is a direct connection between voltage gain and power gain. Under appropriate approximations, if the voltage gain is expressed in terms of circuit resistances and the current gain (?), then the power gain becomes proportional to the square of the voltage gain scaled by the ratio of the internal to load resistances. Consequently, the ratio of power amplification to voltage amplification ends up being equivalent to the current gain ?, linking these two measures of amplification directly.

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