Question
In addition to continuous radiation, fluorescent lamps emit some visible lines from mercury. A prominent line has a wavelength of $436 \mathrm{nm}$. What is the energy (in $\mathrm{J}$ ) of one photon of it?
Step 1
We can use the formula: v = c / λ where v is the frequency, c is the speed of light (approximately 3.00 x 10^8 m/s), and λ is the wavelength. Given the wavelength λ = 436 nm, we need to convert it to meters: λ = 436 nm * (1 m / 10^9 nm) = 436 x 10^-9 m Now, Show more…
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