00:03
In this equation, we are looking for the value of z.
00:08
We're using z sub 1 and z sub 2 to do so.
00:13
Now the equation we're going to use to do that is z equals z sub 1 multiplied by z sub 2, divided by z sub 1 plus z sub 2.
00:28
First thing we need to do is substitute our given values, into this equation.
00:37
So we have z1, 1 plus 2i multiplied by 3 minus 2i.
00:46
All of that divided by 1 plus 2i plus 3 minus 2i.
00:56
Looking at our numerator, we are going to use the foil method to guide our work first, outside, inside, last.
01:05
So we have 3 minus 2i plus 6i minus 4 i squared, all of that divided by, and then here we're going to distribute our operation to get rid of those parentheses.
01:21
So we're going to say 1 plus 2i plus 3 minus 2i...