In an acid-base titration, 23.91 mL of an NaOH solution are needed to neutralize 24.58 mL of a 0.1002 M HCl solution. To find the molarity of the NaOH solution, we can use the following procedure:
a. First note the value of $M_{\mathrm{H}^{+}}$ in the HCl solution.
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b. Find $M_{\mathrm{OH}^{-}}$ in the NaOH solution. (Use Eq. 3.)
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c. Obtain $M_{\mathrm{NaOH}}$ from $M_{\mathrm{OH}^{-}}$
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