00:01
Hello everyone.
00:02
In this problem, we are asked to calculate at what speed a spaceship has to travel to a distance star that is 450 light years away, so that during the round trip, so on the trip going there and on the trip coming back, we could only get 20 years older.
00:23
So what we want to do is we want to cover a total distance of 900 light years, and in that time, we want to age 20 years, i .e., as we're traveling in a spaceship, we want the proper time elapsing in that traveling spaceship frame to be 20 years.
00:43
So first of all, what we have to do is we have to figure out what this distance is, or essentially, what is the time that is going to be.
00:53
Dilating that we're going to look at.
00:55
So in the original frame in which the spaceship is traveling like in a let's say the rest frame of planet earth, the speed of the spaceship is going to be v, right? so this variable v and is going to travel to a distance of 450 light years and then back.
01:16
So the total time that it's going to take is going to be moving at this speed it will be d over v, so 2 times l over v.
01:28
So that's a total time taken in hour frame.
01:31
And this time taken in our frame is going to be the dilated time t -prime measured in the spaceship frame.
01:39
So we're going to include the gamma factor next to t -prime in this case.
01:46
So then we have that d over v is equal to gamma times d -prime, where t -prime is tau, which is the proper time in the spaceship.
01:53
Frame which is 20 years.
01:55
So then we just have to do a bunch of algebra.
01:57
So we put in the gamma factor in its full glory.
02:01
So it's 1 over root of 1 minus v squared over c squared.
02:04
We square everything after dividing both sides here by t prime.
02:11
So squaring everything gives us d over v t prime, all squared, is equal to 1 over 1 minus v squared over c squared.
02:19
Then we multiply fruit by 1 minus 2 squared over c squared and multiply 3 by v squared.
02:25
And then we essentially just rearrange, just follower nods.
02:28
And i was like, expand this bracket.
02:31
You're going to have d over t prime squared minus d over t prime squared as v squared over c squared.
02:38
So we move the v squared over c squared term to the other side and factorize v squared.
02:43
That gives us this factor in the bracket over here.
02:46
And then we divide by that factor.
02:50
And we essentially end up with v being equal to d over t prime over the square root of one plus d over t prime c or squared.
02:59
So then now we are ready to plug you the numbers...