in-an-effort-to-tighten-a-bolt-a-force-mathbff-is-applied-as-shown-in-the-figure-above-if-the-distan

Question

In an effort to tighten a bolt, a force $\mathbf{F}$ is applied as shown in the figure above. If the distance from the end of the wrench to the center of the bolt is 20 $\mathrm{cm}$ and $F=20 \mathrm{N},$ what is the magnitude of the torque produced by F? 
(A) 1 $\mathrm{N} \cdot \mathrm{m}$
(B) 2 $\mathrm{N} \cdot \mathrm{m}$
(C) 4 $\mathrm{N} \cdot \mathrm{m}$
(D) 10 $\mathrm{N} \cdot \mathrm{m}$

Khoobchandra Agrawal · Accepted Answer

Hi everyone thought is to find us are into perpendicular force. Orange 0.2 perpendicular forces continue to Oh, so talk. You will get for the nutrient to meter. Thanks. Oh, yeah. Mhm. Mm. Okay, that&#x27;s all. Thanks for watching it.

Lisa Tarman · Answer

For number 45. There&#x27;s a ranch And there was a force of 80 newtons, That is .25 m from the pivot point here basically where the bold is, It was a force of 80 and we want to know what the torque is. Well, torque is the lever arm distance times the force. Mhm. And we know that the liver arm is .25 And we know the forces 80. So we just multiply And we get that to work is going to be 20 Newton m. And then in the next part it wants to know what force is needed if the force has moved into its only 10 cm away to get that same to work. So I&#x27;m gonna do this force. So again, um Now I know my Twerk is 20 for partying And a new my new lever arm is .100 and I want to find this force. So I just divide both sides by .1. But And I get that my forces 200, So there will be 200 newton&#x27;s and then part see it asked if that would depend on the direction of the force? It definitely does. I I assumed these were perpendicular forces. If they weren&#x27;t perpendicular forces, they would have to be larger to get the same amount of torque. So, I assumed, and the force was perpendicular, because the direction does matter.

Averell Hause · Answer

you here for party, we confound. Calculate the Torque Tao. This would be equaling to the force times the are this would be the radius or essentially the distance from the force to the axis of rotation. And so this would be equaling the force of 165. Newton&#x27;s multiplied by 1650.140 meters, and this is equaling 23.1 Newton meters. This would be our answer for part a and then for port be won&#x27;t we want to convert this so we have the torque equaling 23.1 Newton meters. There are 0.2248 pounds for everyone Newton and then we have 3.281 feet for every one meter. And so this is equaling approximately 17.0 foot pounds. This would be our answer in foot pounds. That is the end of the solution. Thank you for watching

Mayukh Banik · Answer

dark. It was R cross F. The magnitude is given by 0.14 meter, much bite by 1 65 Newton equals two. Indeed, 3.1 new don&#x27;t meet it now That also equals 23.1 Newton meter dimes convert pound into you done and feet in do meter, and that comes out to be 17 food bones.

Jose Hannan · Answer

Hello, everybody. In this video, we&#x27;ll be showing you how to solve Exercise 49 chapter 13 Section four of calculus, early insurance and dental. Now, in this problem, they tell us that we have a bolt here that goes into the page and perpendicular to it with the page, we have a wrench that is 0.25 meters long and at the end of this ridge of force of 20 Newtons is applied at an angle of 45 degrees. And with this they want us to determine the magnitude of the tour here at the bolt produced by this force on this red. Not to do this, we&#x27;re going to use the euro 13.3, which states the magnitude of the cross product of two vectors, such as or cross F, which equals the torch, is equal to the magnitude of, or friends and magnitude of f just the product of the magnitudes of both factors times the sign of their angle of separation now, or is a vector that extends from the pivot point to the place where the force is applied as drawn. And so we know that, or has a magnitude of 0.25 meters just the length of the wrench. And we know that F has a magnitude of 20 Newtons and then we also know that as or is along the wrench, that f is applied at a 45 degree angle to our so Therefore, we also know data equals 45 degrees. And with that we can directly calculate this magnitude we have that the magnitude of this torque is equal 0.25 meters times 20 Newton times the sign of 45 degrees. This is equal 0.25 times 20 which is just five times one over route to Newton meters. So we see. But the magnitude of this torque is equal to five, divided by the square root of two Newton meters. And this is our answer. The problem. So that&#x27;s how you solve exercise 49

Cameron Bunney · Answer

by the today, we&#x27;re going to calculate the magnitude of talk that happens when If we take, um, some boat centered. Oh, and then we have a no 00.25 meter long, uh, wrench, and we apply 20 newtons off. Forced to it. We&#x27;re looking at the magnitude of talk when we&#x27;re at a 45 degree angle. Well, when this is the angle Ah, uh, where the force is applied. So talk is R cross F, and the magnitude of talk is matured of our rented a bath times sine of the angle between them. So 45 degrees is pi over four size of our is not a 0.25 then, Ah, we have F, which is 20 and then sign pyre before the sign of pie before is Route 2/2. So this is 20 over for times route to over two. So we can divine by foreign. We get five, said his five route to over to

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In the figure above, what is the torque about the…

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