00:01
So here we know that an object of mass m, this would be the mass of the object, would be equal to the density of the object row times v, floating in a liquid of density, we could say it is floating in a liquid of density, p liquid.
00:17
Now, this is going to be able to float if the downward pull of gravity is equal to the buoyant force.
00:24
So we can say that here, m .g must be equal to the density of the liquid times g times the volume that is submerged in the liquid, where v sub, of course, again, this would be the portion of the object that is submerged.
00:42
So we can then say that the density of the object divided by the density of the liquid would be equal to the volume that is submerged, divided by the volume v of the object.
00:53
Now, for the fraction, when the liquid is water, we can say that here, this is going to be equal to one.
01:04
So because the object floats fully submerged, this means that the object has the same density as water.
01:12
We can assume that the block maintains an upright orientation...