00:02
From the statement of the problem, we know that we have two types of ions in a solution that creates a current.
00:08
The first is that of the ca2 plus ion, which has a charge of 2e, and the number of these ions is 3 .24 times 10 to the 18, and they flow in a direction from b to a in half a minute.
00:28
The next type is that of the cl minus, which has a charge.
00:33
Minus e and the number of these ions is 5 .11 times 10 to 18 and they flow from a to b in half a minute.
00:43
And e is the elementary charge given to 1 .6 times 10 to minus 19 coulumps.
00:52
We're asked to find the current in the solution and the direction in which it flows, either from a to b or b to a.
01:03
So in the next page we'll solve this.
01:06
And what will do this is to first determine the total charge that's carried by each of the ions.
01:14
So the total charge, q, ca2, plus, will be the q, ca2, plus, times the number of these ions.
01:32
So the charge it carries and the number of them that will give the total charge.
01:41
So this we know is 2e times 3 .24 times 10 to the 18, which is 2 times 1 .6 times 10 to the minus 19, kulams times 3 .24 times 10 to the 18.
02:22
Okay.
02:23
And now i won't compete this number at the moment.
02:25
And i'll just leave it as is.
02:28
And then for the cl minus ions, well, again, we have q, cl minus, times the number of the cl minus ions, which is minus e, and then the number of them, which is 5 .11 times 10 to the 18, which is minus 1 .1, which is minus 1.
02:59
0 .6 times 10 to the minus 19 columns times 5 .11 times 10 to the 18...