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In an RLC circuit a second capacitor is added in series to the capacitor already present. (a) Does the resonance frequency increase, decrease, or stay the same? (b) Choose the best explanation from among the following: \begin{equation}\begin{array}{l}{\text { I. The resonance frequency stays the same because it depends }} \\ {\text { only on the resistance in the circuit. }} \\ {\text { II. Adding a capacitor in series increases the equivalent capaci- }} \\ {\text { tance, and this decreases the resonance frequency. }} \\ {\text { II. Adding a capacitor in series decreases the equivalent capaci- }} \\ {\text { tance, and this increases the resonance frequency. }}\end{array}\end{equation}
a) see workb) see work
Physics 102 Electricity and Magnetism
Chapter 24
Alternating-Current Circuits
Current, Resistance, and Electromotive Force
Direct-Current Circuits
Electromagnetic Induction
Alternating Current
Cornell University
Simon Fraser University
University of Winnipeg
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the restaurant frequency in on our little scene, sir, Quit is getting by the falling relation. The frequency is equals to one divided by the look tense times the capacitors Now remember the following by adding a new capacitor in sceneries with the existing one, we will get a new equivalent capacitance that is a smaller than the previous one. So what happened with the frequency is that as we decrees the capacitance, the frequency will increase So the resonant frequency will increase when we add in a capacitor in Siri's with the existing one. And the best explanation before that's phenomenal is turned one.
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