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In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 1.7 m/s. However, this speed is inadequate to compensate for the kinetic friction between the puck and the ice. As a result, the puck travels only one-half the distance between the players before sliding to a halt. What minimum initial speed should the puck have been given so that it reached the teammate, assuming that the same force of kinetic friction acted on the puck everywhere between the two players?

6.8 m / s

Physics 101 Mechanics

Chapter 6

Work and Energy

Work

Kinetic Energy

Cornell University

Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

Hope College

Lectures

03:47

In physics, the kinetic energy of an object is the energy which it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body in decelerating from its current speed to a state of rest. The kinetic energy of a rotating object is the sum of the kinetic energies of the object's parts.

02:08

In physics, work is the transfer of energy by a force acting through a distance. The "work" of a force F on an object that it pushes is defined as the product of the force and the distance through which it moves the object. For example, if a force of 10 newtons (N) acts through a distance of 2 meters (m), then doing 10 joules (J) of work on that object requires exerting a force of 10 N for 2 m. Work is a scalar quantity, meaning that it can be described by a single number-for example, if a force of 3 newtons acts through a distance of 2 meters, then the work done is 6 joules. Work is due to a force acting on a point that is stationary-that is, a point where the force is applied does not move. By Newton's third law, the force of the reaction is equal and opposite to the force of the action, so the point where the force is applied does work on the person applying the force. In the example above, the force of the person pushing the block is 3 N. The force of the block on the person is also 3 N. The difference between the two forces is the work done on the block by the person, which can be calculated as the force of the block times the distance through which it moves, or 3 N × 2 m = 6 J.

01:58

A hockey player hits a pu…

03:49

$\bullet$$\bullet$ A hocke…

01:48

What coefficient of fricti…

01:06

A hockey puck leaves a pla…

01:50

A hockey player strikes a …

02:43

A hockey stick is in conta…

04:25

Force Times Distance I At …

02:25

A hockey puck is given an …

02:37

An ice hockey forward with…

01:03

A hockey puck slides with …

02:30

A hockey puck sliding alon…

04:30

A hockey puck slides over …

02:10

So here we have our puck. Unless I say that this park is moving at some initial velocity V and then it moves over some distance s and over that distance s its velocity is becoming zero. So the final velocity is equal to zero. So in this case, what we do have is there is a force which is acting on it and that forces the resisted for so we can say negative F s work is equal to the change in kinetic energy. So 1/2 m times zero minus me squid or, in other words, negative f s is equal to 1/2 m v squared. So what we're told in the first case is that when the speed is 1.7 meter per second instead off going all the way to this distance d the puck stops at a distance which is equal to D over too. And we want this party to go all the way to diesel. What should be the speed? So from here, what we are seeing is that you can write down the d is proportional to r s is proportional to so we can write down s is proportional to the square. So if we want to double s so when we can we can write here that when we have d over too. Then it corresponds to 1.7 meter per second. But we really want the distance to be D. So we're looking for this V squared value and when it's a proportionality, then we can solve this for VI and me comes out to be equal to 6.8 meters per second.

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