🎉 Announcing Numerade's $26M Series A, led by IDG Capital!Read how Numerade will revolutionize STEM Learning Oh no! Our educators are currently working hard solving this question. In the meantime, our AI Tutor recommends this similar expert step-by-step video covering the same topics. Numerade Educator ### Problem 2 Easy Difficulty # In Conceptual Example 8.1 (Section 8.1 ), show that the iceboat with mass$2 \mathrm{~m}$has$\sqrt{2}$times as much momentum at the finish line as does the iceboat with mass$m$. ### Answer ##$\sqrt{2} p_{A}\$

#### Topics

Moment, Impulse, and Collisions

### Discussion

You must be signed in to discuss.
##### Andy C.

University of Michigan - Ann Arbor

##### Farnaz M.

Simon Fraser University

Lectures

Join Bootcamp

### Video Transcript

{'transcript': "Our question says to show that the kinetic energy K of a particle of mass M is related to the momentum P is equal to the square root of K squared plus two K M C squared. See? Okay, well, we're gonna go ahead and use equation 36 deaths 11 and 36. That's 13 of the 1st 1 says E is equal to que plus m c squared. So the total energy is equal to the kinetic energy. Plus the rest mass energy and PC squared is equal to e squared minus M c squared. Squared. Okay, well, let's plug in our value for E um, on the left side of the equation when I just marked by a star here into here, we're just pointed with zero. So we have PC squared is equal to okay plus M c squared, which is our expression for the total energy that's all squared minus M. C squared squared. Okay, so if you carry out the square operation there for K plus M C squared, that's equal to K squared plus to K. M. C squared and then plus M c squared squared. But then we also have a minus m c squared squared. So those two terms, we're just gonna cancel So we could just leave it as this case Square plus two k and C squared and we want to solve for P. So we're gonna have P is equal to first. We'll take the square root of both sides a square, root this side right, and then you square it this side and then we'll divide, uh both sides by sea. So you'll end up with the square root of K swear plus to K. M. C squared, and all of that is divided by sea. And that was the expression we were asked to show so we can box it in. That's our solution."}

University of Kansas

#### Topics

Moment, Impulse, and Collisions

##### Andy C.

University of Michigan - Ann Arbor

##### Farnaz M.

Simon Fraser University

Lectures

Join Bootcamp