00:01
Okay, so here we have that our null hypothesis is going to be that mu is greater than equal to 400.
00:06
Our alternative hypothesis is that mu is less than 400, where here mu is the population mean.
00:12
So then we have the sample mean, x bar, be equal to 381 .35, and our standard deviation is 48 .60.
00:19
And we have the sample size and is going to be equal to 15.
00:23
So then the population standard deviation is not known, and the sample size is small.
00:28
So one sample t test is going to be used to test the claim.
00:32
So the test statistic, t -calc, is going to be equal to x bar minus mu not.
00:38
So it's 381 .3 .35 minus 400 and then divided by s over the square of n.
00:46
So 48 .60 divided by the square root of 15 is going to be equal to negative 1 .486.
00:55
So our degrees of freedom is n minus 1, which is 14.
00:59
So then using excel, the excel function here for the left -tailed p test, and we get our p value is going to be equal to 0 .0797.
01:13
So let our significance level alpha be 0 .05...