00:01
In december 2011, consumer reports published their study of labeling of seafood sold in new york, new jersey, and connecticut.
00:06
They purchased 190 pieces of seafood from various kinds of food stores and restaurants in the three states and genetically compared the pieces to standard gene fragments that can identify the species.
00:17
Lab results indicated that 22 % of these packages of seafood were mislabeled, incompletely labeled, or misidentified by store restaurant employees.
00:25
We want to construct a 95 % confidence interval for the proportion of all seafood packages in the local.
00:30
Those three states that are mislabeled or misidentified.
00:37
Here's what we know.
00:38
We know that n is 190, that p hat is 0 .22, and that we want a c of 0 .95.
00:50
And so for our confidence of 0 .95, we're going to use a z score of 0 .025, half of it.
01:03
So using the normal probability table in the appendix back of the book, you'll see that that core corresponds to a z score of 1 .96.
01:11
And so we can then find the margin of error.
01:14
It's using that number times the square root of p hat, which is 0 .22 times 1 minus 0 .22 over n, which is 190.
01:33
So 1 .96 times the square root of 0 .22 times 1 minus 0 .22 over 190 gives us 0 .0589.
01:51
So the boundaries of the confidence interval are going to be p hat minus and plus our margin of error.
02:00
So p hat is 0 .22...