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Today we're talking about drosophilia again, which is a fruit fly.
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They're commonly used in biology and genetics problems for a variety of reasons, mainly dealing with.
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There's not really any laws about torturing them, and they're really easy to have reproduced quickly.
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Okay, so we're giving some information.
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Genetics problems are always a little scary, but you just need to slowly go through them.
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I have typed out a bunch right here, the information that we need combined with the stuff i figured out.
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Okay.
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So from your textbook, i figured out that this is right here.
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Sorry, i'm grabbing my.
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Okay.
01:03
So this textbook, okay.
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Moving on, it's asking us basically, we have recessive gray body, purple, eyes pr, red eyes pr plus, residual wings vg, and that those are recessive to normal wings, which are vg plus.
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The loci encoding these straights is linked, and then your map distance is these units right here.
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It's usually done as mu.
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That's map units.
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So our given interference is 0 .05, and we're trying to figure out if, a fly that has a black body purple eyes and vestigial wings, crossed with a homozygous for gray body, red eyes, and normal wings.
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And then that female progeny is crossed with males that have a black body purpleized and vestigial wings.
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Then we're trying to figure out if a thousand progeny are produced by this test cross, what will the phenotypes be and proportions of the progeny? okay.
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So pause at any point, if i'm going to quickly.
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Basically, we have to write down the information we need.
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We know that the coefficient of coincidence is 0 .5 because it's just one minus interference, which is 0 .05, so it's 0 .05, i mean 0 .5, sorry, 0 .5.
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As a recombinant frequency comes from both single and double crossover progenies.
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First, we have to calculate the number of double crossover progeny.
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The answer is 6 or 0 .06 % and for the bwpr adds 13 or 13 % and we know that the coefficient of coincidence is 0 .5, right? we did that earlier.
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And so observed double crossovers over expected double crossovers.
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We know that there's a thousand total.
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0 .05 equals observed double crossovers.
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Divided by 0 .06 divided, i mean, times 0 .13 times 1 ,000.
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Okay? those are all underneath.
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Extra parentheses, so you're not confused.
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Parentheses are your friend.
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We do that math.
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Figure out 7 .8.
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Observe double crossovers equals that.
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3 .9, rounded to 4.
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Best around genetic problems because they're theoretical anyway...