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In each of the following exercises, solve the given inequality.$$\frac{x^{2}-16}{x^{2}-25}>\frac{20}{11}$$

$x \leq-3$ or $x=0$ or $^{1} / 2<x \leq 2$

Algebra

Chapter 0

Reviewing the Basics

Section 5

Solving Non-Linear Inequalities

Equations and Inequalities

Missouri State University

Idaho State University

Lectures

09:00

In each of the following e…

02:45

01:23

02:25

03:13

03:27

01:16

04:32

03:31

03:07

03:18

03:03

03:51

03:26

02:40

03:12

04:02

02:11

so if you haven't watched the video on number 53 I would go do that one first. Since the only difference between 53 55 is thesis ein we have right here. So in 53 it's just flipped with equals and here is just strictly larger than so if we actually go and look at the work we did in 53. So this is essentially what we did in 53. Um, so we created this sign chart here, but it was actually for, like, this expression right here so you can see, like, I multiplied by a negative side to foot the sign, but this shares the same solutions as the one we started with. So what we could do is if the only difference is we had or this was flipped around is just right. The interval in the opposite, or fill in the gaps or this aan den. We just need to remember to exclude these in points since we have strictly less than here. So we could come over here and do that same thing. So if we were to just kind of fill in the gaps for this So we have negativity to negative six, which the gap in between here would become. So would be negative. Six to negative five. Remember, we're excluding negative five there, Then we union. Okay, so then we come over here on we fill in the gap in between these, which is going to be 5 to 6. And again, remember, we exclude each of those, and so that would be our solution. Say I will. Go ahead. Watch the video on 53. See how we got this sign chart on Ben. Once you complete 53 you could just say Okay, Well, since we have all the solutions for 53 then these are going to be all the solutions for 55. Yeah, so we just scoot down. So, yeah, that there will be our solution.

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