In each of the following, find the point of intersection of the two given lines, and if they do not intersect, explain why.
a) $L_{1}: r=(2,2,3)+t(1,3,1)$
$L_{2}: r=(2,3,4)+t(1,4,2)$
b) $L_{1}: r=(-1,3,1)+t(4,1,0)$
$L_{2}: \mathbf{r}=(-13,1,2)+\mathrm{f}(12,6,3)$
c) $L_{1}: r=(1,3,5)+t(7,1,-3)$
$L_{2}: \mathbf{r}=(4,6,7)+t(-1,0,2)$
d) $L_{1}:\left(\begin{array}{l}x \\ y \\ z\end{array}\right)=\left(\begin{array}{l}3 \\ 4 \\ 6\end{array}\right)+t\left(\begin{array}{r}-2 \\ 1 \\ -1\end{array}\right)$
$L_{2}:\left(\begin{array}{l}x \\ y \\ z\end{array}\right)=\left(\begin{array}{r}5 \\ -2 \\ 7\end{array}\right)+s\left(\begin{array}{r}-4 \\ 2 \\ -2\end{array}\right)$