Question
In each part, find the standard equation of the sphere that satisfies the stated conditions.(a) Center (1,0,-1)$;$ diameter $=8$(b) Center (-1,3,2) and passing through the origin.(c) A diameter has endpoints (-1,2,1) and (0,2,3)
Step 1
(a) Given that the center of the sphere is at (1,0,-1) and the diameter is 8, the radius is half the diameter, which is 4. Substituting these values into the standard equation, we get: \[(x-1)^2 + (y-0)^2 + (z+1)^2 = 4^2\] (b) Given that the center of the sphere Show more…
Show all steps
Your feedback will help us improve your experience
Carson Merrill and 88 other Calculus 3 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In each part, find the standard equation of the sphere that satisfies the stated conditions. (a) Center (7,1,1)$;$ radius $=4$ (b) Center (1,0,-1)$;$ diameter $=8$ (c) Center (-1,3,2) and passing through the origin. (d) A diameter has endpoints (-1,2,1) and (0,2,3) .
Find the standard equation of the sphere. $$ \text { Endpoints of a diameter: }(1,0,0),(0,5,0) $$
Functions of Several Variables
The Three-Dimensional Coordinate System
For the following exercises, find the equation of the sphere in standard form that satisfies the given conditions. Center $C(-4,7,2)$ and radius 6
Vectors in Space
Vectors in Three Dimensions
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD