Question
In Eq. (11) for the multistage rocket take the limit $n \rightarrow \infty$, be convinced that its limiting speed is determined via the formula for an ideal rocket from exercise 4. Why do their results coincide?
Step 1
This equation typically gives the final velocity of an n-stage rocket as: $$v_f = v_e \sum_{i=1}^{n} \ln\left(\frac{M_i}{M_i - m_i}\right)$$ where: - $v_f$ is the final velocity - $v_e$ is the exhaust velocity (assumed constant for all stages) - $M_i$ is the Show more…
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3. Multistage Rocket. Recall the expression for the final speed at burnout of a rocket with no external net forces can be written as v = v0 + vex ln(m0 / mf) where v0 is the initial speed, vex is the speed of the exhaust relative to the rocket, mf is the final mass, and m0 is the initial mass. Thus, the final speed of the rocket is limited by mass ratio at burnout μ = m0/mf and the exhaust speed vex. To improve the situation somewhat, engineers have designed multistage rockets, in which the fuel in each stage is consumed and then the fuel container jettisoned, reducing the overall mass for the next stage. Consider such a multistage rocket consisting of n stages, each with exhaust speed vex and equal mass ratio at burnout μ. Take any net external forces to be zero and the initial speed of the rocket to be zero. Show that the final speed of the nth stage is v = n vex ln(μ).
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