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Hey everyone, this is question number 15 from chapter 21.
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In this problem, we're asked to look at example 21 .3, which is about three -point charges.
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Similar to question 13, if you've looked at that.
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But we have three -point charges on a line.
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I went ahead and drew a quick diagram.
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We have q1, one nano -culem at x equals 2.
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It's in the middle.
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Q2, 3, minus 3 nanoculams, and that is at x equals 4 centimeters.
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And then q3, positive 5 nanoculams at x equals 0.
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So we are asked to find the net force on q1.
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So when we're dealing with net forces, we're going to have the force of 3 on 1, and we're going to have the force of 2 on 1, and then we're going to add those together.
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And if you notice, the force 1 is positive, q2 is negative.
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So that's going to be attractive because it's opposites.
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And then 1 and 3 are both positive, so those are going to be repulsive.
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So the net motion is going to be to the right to the positive x direction.
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So i wrote out kulam's equation just as a reminder.
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You should know this by now.
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But we can go ahead and start by solving for the force of two on one.
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So that's going to equal k, which is 9 times 10 to the 9th, newton meters cubed per kulum squared.
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And then q2 is minus 3...