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In Example 8.14 (Section $8.5 ),$ Ramon pulls on the rope to give himself a speed of 0.70 $\mathrm{m} / \mathrm{s}$ . What is James's speed?

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$v_{J}=0.47\mathrm{m/s}$

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

University of Washington

University of Sheffield

McMaster University

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

04:44

In Example 8.14 (Section 8…

02:49

point) person is pulling b…

02:27

A boat is pulled into a do…

05:40

Refer to Problem 17. Suppo…

04:16

03:34

02:52

A boat is being pulled tow…

01:07

Refer to Problem 9. Suppos…

in this question to friends. James and Ramon are playing tug of war. Ramon has a mass off 60 kg and James has a mass off 90 kg. At some point in time, Ramon suddenly pulls the rope and achieves a speed off 0.7 m per second to the left. By the principle of conservation of momentum, we expect that James will also move with some speed to the right. In this question, we have to calculate what is the speed that James achieve. For that, we're going to use the principle of conservation of momentum. That principle tells us that the net momentum is conserved in any kind of situation where no external forces are acting on our system, which is just our case. So applying the principle of conservation of momentum, we have the following the momentum before the pool is equal to the momentum. After the pool. Let me use these reference frame where everything that points the right is positive. Then in this reference frame, we have the following. Before there was no one moving, so the net momentum before is equals to zero after the pool, both off them are moving James with a mass off 90 kg is moving to the right the positive direction off a reference frame with velocity V. At the same time, Ramon, with a mass off 60 kg, is moving to the left with a velocity off 0.7 m per second. It has a negative sign because it points to the negative direction off our reference frame. Now all we have to do is solve this equation for V. We do that as follows. We begin by sending this term toe the left hand side. So we have 60 times 0.7 is equal to 19 times V. Then we send 90 to the other side dividing. So we have V is equals to 60 times 0.7, divided by 90 by Soviets calculation. We get a velocity off approximately 0.47 m per second to the right and this is the answer to this question.

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