00:01
If we start off with a, and if l equals 0, then da over dt equals 2a times 1 minus 0 .001a.
00:18
So then da over dt equals 0.
00:24
And then if a equals 0 or a equals 1 over 0 .001, that equals 10 ,000.
00:38
So since d -a, d -t is greater than 0, we expect the afib population to increase to 10 ,000 for these values.
01:01
Of a.
01:05
So since dadt is less than zero, well for the increase it is zero, a, 10 ,000, and then for dadt is less than zero, we expect the afid population to decrease to 10 ,000 for these values of a, and that would be a is greater than 10 ,000.
01:49
So in the absence of ladybugs, we expect the afip population to stabilize at 10 ,000.
01:57
For part b, a prime equals 0, and l prime also equals 0...