Question

In Exercise 5.5-1 we said our model of hashing $n$ items into a table of size $k$ is that of an independent trials process with $k$ equally likely outcomes in each trial. In an earlier section we said our model of hashing has a sample space of all possible hash functions, thought of as sequences that tell us for, each location, where it hashes to. We regarded all sequences (and thus all hash functions) as equally likely. Are these two models of hashing in conflict? Why or why not? No vague answers allowed.

    In Exercise 5.5-1 we said our model of hashing $n$ items into a table of size $k$ is that of an independent trials process with $k$ equally likely outcomes in each trial. In an earlier section we said our model of hashing has a sample space of all possible hash functions, thought of as sequences that tell us for, each location, where it hashes to. We regarded all sequences (and thus all hash functions) as equally likely. Are these two models of hashing in conflict? Why or why not? No vague answers allowed.
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Discrete Mathematics and its Applications
Discrete Mathematics and its Applications
Kenneth H. Rosen 4th Edition
Chapter 5, Problem 7 ↓

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Step 1: The model of hashing as an independent trials process with k equally likely outcomes in each trial means that when hashing an item, each of the k slots in the table is equally likely to be the location where the item is stored.  Show more…

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In Exercise 5.5-1 we said our model of hashing $n$ items into a table of size $k$ is that of an independent trials process with $k$ equally likely outcomes in each trial. In an earlier section we said our model of hashing has a sample space of all possible hash functions, thought of as sequences that tell us for, each location, where it hashes to. We regarded all sequences (and thus all hash functions) as equally likely. Are these two models of hashing in conflict? Why or why not? No vague answers allowed.
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