00:01
In this problem, we have to use our knowledge of differential calculus and linear approximation and apply it to a concept that we're given, which is blood concentration or alcohol concentration, and we're given a function for it.
00:17
So we can manipulate it using linear approximation.
00:22
So the first thing that we should know for part a is that x is equivalent to 1, and dx or delta x is 0 .2.
00:31
So the first step that we should take is take the derivative of the function we're given a.
00:36
We'll take da over dx and we'll have 0 .01893x squared minus 0 .092x plus 0 .1012.
00:50
And then we can use or essentially manipulate this equation to say that delta a, pardon me, delta a is equivalent to everything we had before, but we'll multiply by delta x.
01:04
And this allows us to plug in the values we're given for x and dx.
01:10
So that's exactly what we're going to do.
01:12
Wherever i see an x, i'll plug in 1, and our delta x or our dx, we would plug in 0 .2.
01:20
And that's what we'll do.
01:22
So we'll have delta a is roughly equal to because remember, this is not the exact derivative.
01:27
Once we plug values in, that's not.
01:29
Not the exact derivative...