00:01
All right, so for part a, we have that at one gigaflap per second, the execution time for the forward phase is just going to be two -thirds times 10 to the sixth, and then just times one.
00:17
So therefore, that's equal here to about 6 .67 times 10 to the fifth seconds.
00:34
So therefore, the time required to perform the forward phase of the gauss jordan elimination on the 100 ,000 or 100 ,000.
00:41
1 ,000, invitable matrix a is 6 .67 times 10 to the 5th seconds.
00:47
And then for part b, we now estimate the time required to perform the backward phase of the gauss -jordan elimination method.
00:57
So we recall, again, the approximate time and perform the gauss -jordan elimination backward phase for an n -by -n matrix is n -squared flops.
01:06
So here, the total gigaflops for the backward phase is n -squared times 10 to the negative -9th...