Question
In Exercises $1-18,$ graph each ellipse and locate the foci.$$\frac{x^{2}}{16}+\frac{y^{2}}{49}=1$$
Step 1
We can rewrite this equation as $\frac{x^{2}}{4^{2}}+\frac{y^{2}}{7^{2}}=1$. From this equation, we can determine the values of $a$ and $b$. The value of $a$ will be $7$ and the value of $b$ is $4$. Show more…
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