Question
In Exercises $1-6,$ find the value of the derivative (if it exists) at each indicated extremum.$$f(x)=-3 x \sqrt{x+1}$$
Step 1
We can identify $u=-3x$ and $v=\sqrt{x+1}$, so we can apply the product rule which states that $(uv)' = u'v + uv'$. Show more…
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