00:01
So the question is, use equation 1 to estimate delta f equals f of 3 .02 minus f of 3.
00:10
And the function we're given is f of x equals x to the 4th.
00:14
So from here we can see that in our problem, we're given delta f in this form, which is also how it is written in the textbook, where delta f is equal to f of a, plus a certain delta x minus f of a.
00:35
So equation one in the book states that when delta x is very small, we can use this approximation, where delta f is approximately equal to f prime at point a times delta x.
00:56
So in order to estimate this delta f value we must find the derivative of f at point a as well as delta x so using 3 .02 and 3 we can we see that delta x is equal to their difference which is 0 .0 and then using this equation here we also see that a is equal two, three.
01:38
And now we will have to differentiate this equation right here, x to the fourth...