Question
In Exercises 105-108, determine the $x$-and $y$-intercepts, if they exist, of the graph of each equation.$$x=2(y-3)^{2}+6$$
Step 1
To do this, we'll set y = 0 and solve for x. x = 2(0 - 3)^2 + 6 x = 2(-3)^2 + 6 x = 2(9) + 6 x = 18 + 6 x = 24 So the x-intercept is (24, 0). Now, let's find the y-intercept. To do this, we'll set x = 0 and solve for y. 0 = 2(y - 3)^2 + 6 We'll first subtract Show more…
Show all steps
Your feedback will help us improve your experience
Raushan Kumar and 95 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Problems $99-108$, (a) find the intercepts of the graph of each equation and (b) graph the equation. $$ 2 x+3 y=6 $$
Graphs
Lines
In Exercises 67–72, use intercepts to graph each equation. $$ 2 x+3 y+6=0 $$
Functions and Graphs
Linear Functions and Slope
In the following exercises, find the intercepts for each equation.. $$ 3 x+y=6 $$
Graphs and Functions
Graph Linear Equations in Two Variables
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD