Question
In Exercises 105-108, determine the $x$-and $y$-intercepts, if they exist, of the graph of each equation.$$x=-(y+2)^{2}-8$$
Step 1
To do this, we'll set y = 0 and solve for x. x = -(0 + 2)^2 - 8 x = -4^2 - 8 x = -16 - 8 x = -24 So the x-intercept is (-24, 0). Now, let's find the y-intercept. To do this, we'll set x = 0 and solve for y. 0 = -(y + 2)^2 - 8 Show more…
Show all steps
Your feedback will help us improve your experience
Xiaomeng Zhang and 56 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Exercises $79-84,$ find the $x$ -intercepts of the graph of each equation. Then use the $x$ -intercepts to match the equation with its graph. [The graphs are labeled (a) through (f).] $$y=(x+2)^{2}-9(x+2)+20$$
Equations and Inequalities
Other Types of Equations
In the following exercises, find the intercepts for each equation.. $$ x-2 y=8 $$
Graphs and Functions
Graph Linear Equations in Two Variables
In Exercises $79-84,$ find the $x$ -intercepts of the graph of each equation. Then use the $x$ -intercepts to match the equation with its graph. [The graphs are labeled (a) through (f).] $$y=x^{-2}-x^{-1}-6$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD