Question
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets.$$\left\{\begin{array}{l}y=x+5 \\y=-x+3\end{array}\right.$$
Step 1
The slope of this line is 1 and the y-intercept is 5. We can start by plotting the y-intercept at the point (0,5). Since the slope is 1, for every 1 unit we move to the right, we move up 1 unit. This gives us a line that looks like this: Show more…
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In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} x=3 \\ y=5 \end{array}\right.$$
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In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} y=-2 x+3 \\ y=-x+1 \end{array}\right.$$
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} x+y=1 \\ y-x=3 \end{array}\right.$$
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