Question
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets.$$\left\{\begin{array}{l}y=3 x-4 \\y=-2 x+1\end{array}\right.$$
Step 1
This equation is in slope-intercept form, where the slope is $3$ and the y-intercept is $-4$. We plot the y-intercept at $y=-4$ and then draw a line with a slope of $3$. Show more…
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In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} y=-2 x+3 \\ y=-x+1 \end{array}\right.$$
Systems of Linear Equations and Inequalities
Solving Systems of Linear Equations by Graphing
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} y=2 x+1 \\ y=-2 x-3 \end{array}\right.$$
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} 4 x+y=4 \\ 3 x-y=3 \end{array}\right.$$
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