Question
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets.$$\left\{\begin{array}{l}2 x+3 y=6 \\4 x+6 y=12\end{array}\right.$$
Step 1
To do this, we find the x-intercept by setting y equal to zero. This gives us $2x = 6$, which simplifies to $x = 3$. Show more…
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In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} 2 x-3 y=6 \\ 4 x+3 y=12 \end{array}\right.$$
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Solving Systems of Linear Equations by Graphing
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} x-y=2 \\ 3 x-3 y=-6 \end{array}\right.$$
In Exercises $11-42,$ solve each system by graphing. If there is no solution or an infinite number of solutions, so state. Use set notation to express solution sets. $$\left\{\begin{array}{l} y=2 x \\ y=-x+6 \end{array}\right.$$
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