00:01
Okay, dokey.
00:01
We want to find values of x that satisfy this equation.
00:04
And probably the easiest method is just to use a quadratic formula.
00:07
And i don't know if you're giving this in your exams, but hopefully you know it off by heart.
00:12
It's minus b plus or minus the square root of b squared minus 4a.
00:19
C over to a when our quadratic takes the form a x whoops you do it we'll do this a little a x squared plus b x plus c okay so we can see our a here is one uh b here is minus two and i'll see here is four so if we put this into our equation here is two is going to just bottom two times one is just two the square root so b square minus two square is four minus now i know you can see we're getting a negative in here uh minus four times one times four four is 16 okay so four minus 16 is equal to uh two plus or minus the square root of minus 12 over two.
01:25
Now, i hope you know, i is equal to the square root of minus 1.
01:32
And if we just take this minus 12 over here, root minus 12, i just want, we can, i hope you know, we can split this up into three times four times minus 1.
01:48
Three times four is 12, minus what is minus 12...