Question
In Exercises $13-26,$ find a formula for the $n$ th term of the sequence.$$\frac{1}{25}, \frac{8}{125}, \frac{27}{625}, \frac{64}{3125}, \frac{125}{15,625}, \ldots$$
Step 1
The numerators are the cubes of consecutive integers, and the denominators are powers of 5. Show more…
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In Exercises $13-26,$ find a formula for the $n$ th term of the sequence. $$\frac{1}{25}, \frac{8}{125}, \frac{27}{625}, \frac{64}{3125}, \frac{125}{15,625}$$
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