Question
In Exercises $13-26,$ find a formula for the $n$ th term of the sequence.$$\frac{1}{9}, \frac{2}{12}, \frac{2^{2}}{15}, \frac{2^{3}}{18}, \frac{2^{4}}{21}, \dots$$
Step 1
The numerators of the sequence are \(1, 2, 2^2, 2^3, 2^4, \ldots\). This suggests that the numerator of the \(n\)th term is \(2^{n-1}\). Show more…
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In Exercises $13-26,$ find a formula for the $n$ th term of the sequence. $$\frac{1}{9}, \frac{2}{12}, \frac{2^{2}}{15}, \frac{2^{3}}{18}, \frac{2^{4}}{21}, \dots$$
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In Exercises 13-26, find a formula for the nth term of the sequence. The sequence $$1,-\frac{1}{4}, \frac{1}{9},-\frac{1}{16}, \frac{1}{25}, \dots$$
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