00:03
In problem number 17, we are told that alpha is the angle 2 ,456 degrees.
00:11
That's abnormally large, and in my opinion, it's a little overkill for what they're trying to accomplish here, but that's okay.
00:18
We can get through it, no problem.
00:21
In fact, i like to take a little bit extra time and do it visually because i think that benefits a lot of learners.
00:28
The fact of the matter is the problems are just basic arithmetic.
00:32
You're just adding or subtracting multiples of 360 depending on what your angle is.
00:37
So let's try to do it visually.
00:40
Maybe that'll improve understanding a little bit.
00:43
So anyway, we want to figure out in what quadrant does the terminal side of that angle end up? and then what is the equivalent co -terminal angle within the first revolution of the circle? so from zero to 360 degrees.
01:00
So literally, if you wanted to do it arithmetic -wise, you would take 2456 and then you would subtract 360 and then subtract 360 again and subtract 360 again until you get into that range of zero to 360.
01:17
And then that's going to be your answer.
01:19
If you want to do it that way, i like to do it visually.
01:24
That's just me.
01:26
All right.
01:26
So let's figure out where this angle of 2 ,000.
01:31
456 degrees is first.
01:34
So we're going to use lots and multiples of 360, right? hopefully i can do the arithmetic without too much difficult.
01:43
So one time around the circle, that's 360.
01:48
Two times around the circle, that's going to be 720...