The binomial theorem states that $(a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k}$, where $\binom{n}{k}$ is the binomial coefficient.
So, for $(a+b)^6$, we have:
$$(a+b)^6 = \binom{6}{0} a^{6} b^{0} + \binom{6}{1} a^{5} b^{1} + \binom{6}{2} a^{4} b^{2} +
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