Question
In Exercises $17-36,$ locate the absolute extrema of the function on the closed interval.$$f(x)=x^{3}-12 x,[0,4]$$
Step 1
To do this, we take the derivative of the function $f(x) = x^3 - 12x$. The derivative is $f'(x) = 3x^2 - 12$. Show more…
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