Question
In Exercises $17-36,$ locate the absolute extrema of the function on the closed interval.$$y=3-|t-3|,[-1,5]$$
Step 1
The critical points are the points where the derivative of the function is either zero or does not exist. In this case, the derivative of the function does not exist at $t=3$. So, $t=3$ is a critical point. Show more…
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