00:01
So in this problem, what we're doing is we're looking at a function, f of x, and by taking its derivative, which will denote as f prime of x, we'll determine some characteristics about the function, namely whether it's increasing or decreasing, and whether we can find any local minimum or maximum.
00:21
So to do this, our first step in solving this type of solution is we'd go ahead and we find the critical numbers.
00:29
And what this means is that we're going to go ahead take f prime of x, that derivative, and set that equal to zero.
00:40
And when we do that, we're going to find if we have any critical numbers.
00:46
And that will tell us how to set up our test intervals when we're trying to determine if the function is increasing or decreasing.
00:55
So once we've solved this equation here, so we found where, f prime of x is equal to zero.
01:05
And if we've gotten any critical numbers, we can then determine whether the function f of x is increasing or decreasing based on the sign of f prime of x.
01:16
So within some test interval, if we find that f of x or f prime of x, the derivative, is greater than zero, this means that f of x is an increasing function, which i'll denote with an upward arrow.
01:32
And conversely, if we find that f prime of x is negative within some test interval, we then find that the function f of x will be decreasing in this interval.
01:50
And if we find that f prime of x is equal to zero, this just means that f of x is constant.
02:07
So once we have these, whether the function is increasing or decreasing along some intervals, once we have those established, we can then use the first derivative test to determine if we have any local minimum or maximum.
02:30
And so what we do is we look along either side of that critical number, so where we break off the test intervals.
02:39
And if we find that the sign of f prime of x goes from positive to negative, this means that we have a relative maximum at this point.
02:56
And if at the point that we find instead it goes from negative to positive, this indicates a relative minimum.
03:10
So now that we've established our rules and the process for using the first derivative test, we're going to go ahead and apply it to this problem where we have a function here, which i'll write out.
03:24
And the function is x minus 1 squared times x plus 3.
03:41
So now to make it easier to derive, i'll go ahead and just expand this.
03:46
So we have x cubed plus x squared minus 5x plus 3.
03:58
And now we can simply take the derivative of that, which will be equal to 3x squared plus 2x minus 5...