Question
In Exercises $19 - 28 ,$ determine the limit graphically. Confirm algebraically.$$\lim _ { x \rightarrow 0 } \frac { \sin ^ { 2 } x } { x }$$
Step 1
We can rewrite this as a product of two limits using the product rule for limits. This gives us $\lim_{x \rightarrow 0} \frac{\sin x}{x} \cdot \lim_{x \rightarrow 0} \sin x$. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Exercises $19 - 28 ,$ determine the limit graphically. Confirm algebraically. $$\lim _ { x \rightarrow 0 } \frac { \sin x } { 2 x ^ { 2 } - x }$$
Limits and Continuity
Rates of Change and Limits
In Exercises $19 - 28 ,$ determine the limit graphically. Confirm algebraically. $$\lim _ { x \rightarrow 0 } \frac { \sin 2 x } { x }$$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD